Respuesta :
Question: Find three consecutive odd integers whose sum is 363
To find the three odd integers, divide 363 by three (since thats the amount of integers you need to find)
[tex]363[/tex] ÷ [tex]3=121[/tex]
Since you need three odd integers and since 121 is an odd integer, find the odd integer right below 121 and the one right above
119 is the odd integer right below 121
121 is the odd integer you kept untouched
123 is the odd integer right above 121
To check, add the integers: [tex]119+121+123=363[/tex]
Answer: 119, 121, and 123
To find the three odd integers, divide 363 by three (since thats the amount of integers you need to find)
[tex]363[/tex] ÷ [tex]3=121[/tex]
Since you need three odd integers and since 121 is an odd integer, find the odd integer right below 121 and the one right above
119 is the odd integer right below 121
121 is the odd integer you kept untouched
123 is the odd integer right above 121
To check, add the integers: [tex]119+121+123=363[/tex]
Answer: 119, 121, and 123
Suppose that k is our odd number.Then k + 2 is the next odd number.And k + 4 is the third odd number.
We want the sum of these numbers to be 363.So we want (k) + (k+2) + (k+4) = 363.So we want 3k + 6 = 363.This gives us 3k = 357, which gives k = 119.
We want the sum of these numbers to be 363.So we want (k) + (k+2) + (k+4) = 363.So we want 3k + 6 = 363.This gives us 3k = 357, which gives k = 119.