Question

helpo with bernoulli differential equation... y'+xy=xy^2 ...?

Answer 1

Using the bernoulli differential equation we proceed like this 
y' = xy^2 - xy
dy / dx = xy^2 - xy
dy = (xy^2 - xy) dx
dy = (x)(y^2-y) dx
dy / (y^2 - y) = x dx
That is how it is solved