Respuesta :

gmany

Answer:

[tex]\huge\boxed{x=6\ \vee\ x=0}[/tex]

Step-by-step explanation:

[tex]2|x-3|+1=7\qquad\text{subtract 1 from both sides}\\\\2|x-3|+1-1=7-1\\\\2|x-3|=6\qquad\text{divide both sides by 2}\\\\\dfrac{2|x-3|}{2}=\dfrac{6}{2}\\\\|x-3|=3[/tex]

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[tex]|a|=\left\{\begin{array}{ccc}a&\text{for}&a\geq0\\-a&\text{for}&a<0\end{array}\righ[/tex]

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Therefore

[tex]|x-3|=3\iff x-3=3\ \vee\ x-3=-3\qquad\text{add 3 to both sides}\\\\x-3+3=3+3\ \vee\ x-3+3=-3+3\\\\\boxed{x=6\ \vee\ x=0}[/tex]