Question

The prices of tickets for the local rock concert were $16 for Friday night and $28 for Saturday night. The total attendance for the two nights was 1090. If the total receipts were $24,232, how many people attended Saturday night?

Answer 1

for thsi you need to think of 2 simulatneous equations=
16f + 28s= 24232
f + s = 1090
We need to find a way to subtract one equation from the other so you can multiply the bottom by 16
so you would get
16f + 28s = 24232
16f + 16s = 17440
Now you can subtract the second one from the bottom one to get
12s= 6792
s= 566
So there were 566 tickets sold on staurday so to find fridasy you can do 1090 -566, which is 524
so on friday night 524 were sold and on saturday there was 566 sold

Answer 2

The number of people that attended the Saturday night concert is 566 people.

The price of the local ticket was $16 for Friday night and  $28 for Saturday night.

let

the attendance on Friday = x

the attendance on Saturday = y

Therefore,

x + y = 1090

16x + 28y = 24232

x = 1090 - y

16(1090 - y) + 28y = 24232

17440 - 16y + 28y = 24232

12y = 6792

y = 6792/12

y = 566

x + 566 = 1090

x = 1090 - 566

x = 524

Therefore, 566 people attended the Saturday night party.

read more: https://brainly.com/question/3455097?referrer=searchResults