Question

Will, Micah and sue went to dinner. Will paid 1/3 of the dinner bill. Micah and sue paid in the ratio of 2:5. If sue paid $6 more Than Will, how much did the dinner cost

Answer 1

$21. If you take 2:5 and double it 4:10, 10 is 6 more than four, so you add the two up (14) and then you have 2/3s of the bill. then you divide 14 in two (7) and multiply 7 by three (21).

Answer 2

Answer : The dinner cost was, $ 42

Step-by-step explanation :

Let the dinner cost be, 'x'

Dinner cost paid by Will = $\frac{1}{3}\times x$

Remaining dinner cost = $(1-\frac{1}{3})x=\frac{2}{3}x$

The ratio of dinner cost paid by Micah and sue is 2:5

Dinner cost paid by Micah = $(\frac{2}{3}x)\times \frac{2}{7}=\frac{4}{21}x$

Dinner cost paid by Sue = $(\frac{2}{3}x)\times \frac{5}{7}=\frac{10}{21}x$

As, Sue paid dinner cost $6 more than Will.

That means,

$(\frac{10}{21}x)=\ 6+(\frac{1}{3}\times x)$

$(\frac{10}{21}x)-(\frac{1}{3}\times x)=\ 6$

$(\frac{1}{7}\times x)=\ 6$

$x=\ 6\times 7$

$x=\ 42$

Thus, the dinner cost was, $ 42