According to the statements, the answer to the question is yes. Even though the initial and final velocities are the same, there is a change in direction for the ball (option D).
Acceleration is the change in velocity, which is a vector, according to the following equation:
[tex] a = \frac{\Delta v}{\Delta t} = \frac{v_{f} - v_{i}}{t_{f} - t_{i}} [/tex]
Where:
[tex] v_{f}[/tex] and [tex] v_{i}[/tex] is the final and initial velocity, respectively
[tex] t_{f}[/tex] and [tex] t_{i}[/tex] is the final and initial time, respectively
In the given image, we can see that the magnitude of the final and initial velocity is the same and that directions are opposites, so the acceleration would be:
[tex]a =\frac{v_{f} - v_{i}}{\Delta t} = \frac{(-5 - 5) m/s}{\Delta t} = \frac{-10 m/s}{\Delta t}[/tex]
With this, we can rule out the options:
A. Although the initial and final velocities are the same, the directions are not.
B. The ball does not need to slow down to change direction.
C. The ball's velocity is not constant (the directions are different).
Therefore, the answer is option D.
Read more here:
- https://brainly.com/question/12134554?referrer=searchResults
- https://brainly.com/question/12134554?referrer=searchResults
I hope it helps you!