Answer:
They will both blink again at 3:12 pm.
Step-by-step explanation:
As indicated by the question, the way to solve is to find the Lowest (or Least) Common Multiple of both numbers.
As such:
[tex]\text{List the factors of 12 and 44:}\\12=2*2*3\\44=2*2*11\\\\\text{Take the common factors only once and multiply them by the non-common factors:}\\2*2*3*11=132 \text{ (LCM)}[/tex]
Now knowing the LCM is 132, we convert those minutes into hours and minutes:
[tex]\frac{132}{60}=2\frac{12}{60} \text{ (2 hours and 12 minutes)}[/tex]
Add this to the original time:
[tex]1:00\text{ pm } + \text{ }2:12 \text{ }= \text{ }3:12\text{ pm}[/tex]