Answer:
t = d/v , 33.3 ns
Explanation:
Since distance, d = vt where v = speed and t = time taken to cover the distance.
Since the distance, d covered by the alpha particle is the length of Rutherford's lab which is 10 m long and the speed of the alpha particle is v = 3 × 10⁸ m/s, the time, t it takes the alpha particle to move from the alpha particle source to the gold foil target is thus
t = d/v
= 10 m/3 × 10⁸ m/s
= 10/3 × 10⁻⁸ s
= 3.33 × 10⁻⁸ s
= 33.3 × 10⁻⁹ s
= 33.3 ns
