PLEASEEEEEEEEEEEEEE HELPPPPPPP PLEASEEEEEE !!!!
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Answer:
[tex]x=\frac{\sqrt{2}}{2}[/tex]
Step-by-step explanation:
The given triangle is an isosceles right triangle, meaning that the 45-45-90 triangle side rule applies. The 45-45-90 triangle side rule states that the two legs (sides that are adjacent to the right angle) are congruent, and the hypotenuse (the side opposite the rights angle) is equal to the leg times the square root of two. Using this property, one knows that the leg is equal to the hypotenuse divided by the square root of two. In this problem, the hypotenuse is equal to (1), and the leg is equal to (x). Therefore, one can say,
[tex]x = \frac{1}{\sqrt{2}}[/tex]
Rationalize the denominator,
[tex]\frac{1}{\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}}\\\\\frac{\sqrt{2}}{2}[/tex]
Answer:
Step-by-step explanation:
a² + b² = c² look familiar? it is the Pythagorean theorem
both side are the same length since both angles are the same some sort of Isosceles triangle rule I think so side 1 = x side 2 = x and hypotenuse = 1
x² + x² = 1²
2x² = 1
x² = 1/2
x = √(1/2) the denominator is NOT rational in this FORM
x = √1 / √2 multiple the numerator and the denominator by √2
x = 1 (√2) / (√2)(√2)
x = √2 / √2²
x = √2 / 2 finding a rational denominators means nothing
just do more work and more typing for me,
a silly MATH rule
x = √2/2 = 0.7071 x = √(1/2) = √(0.5) = 0.7071 the SAME Number
sorry, my rant of the day