Question

The figure below shows the head of a patient being fixed to a
Russell Traction System, where the patient is laying down on his
back on a bed that is inclined by 20° with the horizontal as
shown. The static frictional force between the patient and the
bed is 190N and the coefficient of static friction is 0.4.
(a) Find the weight of the patient.
(b) Find the minimum balancing mass, M that stretches the
patient from

Answer 1

Answer:

a) 505.5

Explanation:

draw all the forces acting on the body then

w cosθ = Fn --> W = $\frac{Fn}{cos\\}$

we can find Fn from

Fs= MEU(s) x Fn