Question

A small dog is trained to jump straight up a distance of 1.1 m. How much kinetic energy does the 7.7 kg dog need to jump this high?

Answer 1

Answer:

83.09 J

Explanation:

The potential energy at the point of the top of the jump is represented by the equation

$mgdeltah$

when the dog jumps, all the potential energy converts to kinetic energy (1/2mv^2). Plugging in the values:

(7.7)(4.184)(1.1) = 83.0907 J