Question

A constant current source supplies a electric current of 200 mA to a load of 2kΩ. When the load changed to 50Ω, the load current will be

8A
9mA
700mA
12A​

Answer 1

Answer:

700ma

Explanation:

all u do is have to add them up.

Answer 2

Ohm's law allows us to calculate the result for the value of the current when we change the resistance of the circuit:

• The current is: i = 8 A

Ohm's law establishes that voltage is proportional to current and we call the constant of proportionality resistance in a circuit.

           V = i R

Where V is the voltage, i the current and R the resistance of the circuit.

They indicate that the source supplies a current of i = 200 mA = 0.200 A at a load of R = 2 kΩ = 2 10³ Ω

Let's find the source voltage.

           V = 0.200 2 10³

           v = 400 V

Now with this voltage let's find the current for the new load of R = 50 Ω

          i = V / R

          i = 400/50

          i = 8 A

In conclusion using Ohm's law we can calculate the result for the value of the current when we change the resistance of the circuit is:

• The current is: i = 8 A

               

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