Question

Given a +b=7 and a-b=3, find:
3^a/3^b

Answer 1

Answer:

First of all you will solve the two equations simultaneously to get the values of a and b after that you use it to find, 3^a /3^b

Step1. a+b=7..... (1)

a-b=3.......(2)

Now take eqn(1) +eqn(2),

Implies 2a=10

Dividing both sides by 2,

Then a=5

Put a=5 into eqn(1),

Implies 5+b=7

b=7-5

b=2

Therefore the values of a and b are 5 and 2

Step2

Now find 3^a/3^b,

Substitute the vaues of a and b into the function.

Implies 3^5/3^2=243/9

=27

Therefore 3^a/3^b=27

Step-by-step explanation:

Above

Answer 2

An equation is formed of two equal expressions. The solution of $3^a \div 3^b$ is 27 or 3³.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

As it is given to us that the sum of a and b is 7, while the difference of a and b is 3, therefore, the two-equation are,

a+b = 7

a-b =3

Now, if we add the two equations we will get, the value of a, therefore,

$(a+b)+(a-b)=7+3\\\\a+b+a-b=10\\\\2a=10\\\\a=5$

Now, if we substitute the value of a in any one of the equation, then we will get the value of b,

$a+b=7\\\\5+b=7\\\\b=2$

Thus, the value of a and b is 5 and 2 respectively.

Now, if we substitute the value of a and b in the problem we will get,

$3^a \div 3^b\\\\=\dfrac{3^a}{3^b}\\\\=\dfrac{3^5}{3^2}\\\\=3^{5-2}=3^3=27$

Hence, the solution of $3^a \div 3^b$ is 27 or 3³.

Learn more about Equation:

https://brainly.com/question/2263981