Answer:
[tex]\frac{x-1}{x+2}[/tex]
Step-by-step explanation:
simplifying the equation: [tex]x^2-3x+2/x^2-1[/tex]
1) Rewrite the equation so it's easier to understand:
[tex]\frac{x^2-3x+2}{x^2-4}[/tex]
2) factor [tex]x^2-3x+2[/tex]:
[tex]x^2-3x+2[/tex] [tex]=> (x-1)(x-2)[/tex]
3) factor [tex]x^2-4[/tex]:
[tex]x^2-4 => (x+2)(x-2)[/tex]
Meaning: [tex]\frac{(x-1)(x-2)}{(x+2)(x-2)}[/tex]
4) Cancel the common factor: [tex](x-2)[/tex] from the numerator and the denominator:
[tex]=\frac{x-1}{x+2}[/tex]