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Answer:
(i) The axis of symmetry is [tex]x = -4[/tex].
(ii) The axis of symmetry is [tex]x = 4[/tex].
(iii) The axis of symmetry is [tex]x = 1[/tex].
Step-by-step explanation:
We proceed to explain how we determine the expression for the axis of symmetry for each case:
(i) [tex]f(x) = 3\cdot (x+4)^{2}+1[/tex]
The expression depicts a vertical parabola, meaning that axis of symmetry is vertical, that is, a function of the form [tex]x = a,\,\forall\,a\in \mathbb{R}[/tex]. This line passes through the vertex of the parabola. The component [tex]x+4[/tex] contains the information of the horizontal component of the vertex, where the axis passes through. Therefore, the axis of symmetry is [tex]x = -4[/tex].
(ii) [tex]f(x) = 2\cdot x^{2} -16\cdot x +15[/tex]
At first we complete the square and factor the perfect square trinomial:
[tex]f(x) = 2\cdot \left(x^{2}-8\cdot x +\frac{15}{2} \right)[/tex]
[tex]f(x) = 2\cdot \left[(x^{2}-8\cdot x +16) +\frac{15}{2}-16 \right][/tex]
[tex]f(x) = 2\cdot (x-4)^{2}-17[/tex]
By applying the approach used in (i), we find that the axis of symmetry is [tex]x = 4[/tex].
(iii) First, we locate the vertex of the parabola, which is (1,-3). The first component of the ordered pair contains all the needed information to determine the equation of the axis of symmetry, which is [tex]x = 1[/tex].