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The width of a rectangle is 7t-1.5 feet and the length is 1.5t + 8 feet. Find the perimeter of the
rectangle.
The perimeter of the rectangle is feet.

Respuesta :

Step-by-step explanation:

✧ [tex] \underline{ \underline{ \large{ \tt{ \: G \: I\:V \: E \: N}}}} : [/tex]

  • Width of a rectangle ( w ) = 7t - 1.5 ft
  • Length of a rectangle ( l ) = 1.5t + 8 ft

✧ [tex] \underline{ \underline{ \large{ \tt{ \: T \: O\: F\: I \: N \: D}}}} : [/tex]

  • Perimeter of the rectangle

✧ [tex] \underline{ \underline{ \large{ \tt{S \: O \: L \: U \: T \: I\: O \: N}}}} : [/tex]

❀ [tex] \boxed{ \large{ \text{Perimeter \: of \: a \: rectangle \: = \: 2(l + w)}}}[/tex]

⟶ [tex] \large{ \tt{2(1.5 \: t \: + 8 \: + 7t - 1.5}})[/tex]

⟶ [tex] \large{ \tt{2(1.5t + 7t + 8 - 1.5)}}[/tex]

⟶ [tex] \large{ \tt{2}(8.5t + 6.5)}[/tex]

⟶ [tex] \large{ \tt{17t + 13}}[/tex]

☄ [tex] \underline{ \boxed{ \boxed{ \tt{Our \: final \: answer : \underline{ \boxed{17t + 13 feet}}}}}} [/tex]

Hope I helped ! ♡

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☞ [tex] \underline{ \underline{ \mathfrak{Carry \: on \: learning}}}[/tex] !! ✎

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