Answer: The pressure in the can is 4.0 atm
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = ?
V = Volume of gas = 0.410 L
n = number of moles = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{3.0g}{44.1g/mol}=0.068mol[/tex]
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]20^0C=(20+273)K=293K[/tex]
[tex]P=\frac{nRT}{V}[/tex]
[tex]P=\frac0.068mol\times 0.0820 L atm/K mol\times 293K}{0.410L}=4.0atm[/tex]
Thus the pressure in the can is 4.0 atm