Question

What is 13th term of geometric sequence whose 7th term is 25 and common ratio is 3

Answer 1

Answer:

18225

Step-by-step explanation:

let 7th term = t7

t7= a.3^(7-1) (common formula of geometric series is a.r^(n-1)

or, 25= a. 3^6

or, a=25/729

now, for 13th term,

t13= a.r^(13-1)

= 25/729 × 3^12

=18225