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N2+H2---2 NH3?
ASSIGN OXIDATION STATES AND
FIND OXIDIZING AND REDUCING
AGENTS?
Please with steps if possible

N2H22 NH3 ASSIGN OXIDATION STATES AND FIND OXIDIZING AND REDUCING AGENTS Please with steps if possible class=

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Answer:

Oxidizing Agent - Nitrogen

Reducing Agent - Hydrogen

Explanation:

The equation of the reaction is given as;

N2 + H2  -->  2 NH3

Oxidation Rules:

- The oxidation number of an element in it's free state is Zero. This means oxidation state of N2 and H2 are Zero.

- The oxidation number of a neutral compound is the sum of the oxidation state of the individual elements and is equal to zero.

- Oxidation Number of Hydrogen in a compound/Molecule is 1 except in hydrides where it is -1

This means that oxidation number of H in NH3 = 1

Oxidation state of N in NH3;

x + 3(1) = 0

x = -3

The reducing agent loses electrons. Loss of electrons is represented by increase in oxidation Number. The oxidation number of H increases from 0 to + 1

The Oxidizing agent gains electrons. Gain of electrons is represented by decrease in oxidation Number. The oxidation number of N decreases from 0 to -3

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