Question

5) A jet plane lands with a speed of 100 m/s and can accelerate at a maximum rate of -5.00 m/s as it comes to rest (n) From the instant the plane touches the runway, what is the minimum time needed before it can come to rest? (b) Can this plane land on a small tropical island airport where the runway is 0.800 km long?​

Answer 1

Answer:

1000 meters, 200 meters

Explanation:

Given: Vi = 100 m/s and a = -5 m/s^2

From uniformly accelerated equation:  v = Vi + a t

then substitute

0 = 100 -5 t

t = 20 seconds

to go from 100 to 0 at -5m/s^2

d = Vi (20) - (1/2)(5)(20)^2

d = 100 (20) - 2.5(400)

= 2000 - 1000

= 1000 meters to stop, runs 200 meters beyond the end of the runway into the harbor where he strikes a passenger ferry.