Question

(THIS IS NOT A TEST OR AN ASSESSMENT QUESTION)
Hugo averages 32 home runs per season with a standard deviation of 2.5. Jacob averages 27 home runs per season with a standard deviation of 1.6. Last season Hugo hit 36 home runs and Jacob hit 31 home runs. Who had more home runs relative to their usual seasonal average? Explain.

Answer 1

Answer:

Jacob had more home runs relative to his usual season average than Hugo did.

Step-by-step explanation:

The key solving this is to express their respective home runs in z-value forms.

Z = (x - ų)/óx

X = Current home runs

Ų = Mean

= Meanóx = Standard deviation

For Hugo,

X = Current home run = 31

Ų = Mean = 27

Óx = Stardard deviation = 1.6

Z = (x - ų)/óx

Z = (31 - 27)/1.6 = 2.5

Hope this helped!!!

Answer 2

The person who had more home runs relative to their usual seasonal average was Jacob.

Calculations and Parameters:

Representing their home runs in z-value forms.

Where

• Z = (x - ų)/óx
• X = Current home runs
• Ų = Mean

= Meanóx = Standard deviation

To find the home run for Hugo,

• X = Current home run = 31
• Ų = Mean = 27
• Óx = Stardard deviation = 1.6

Therefore,

Z = (x - ų)/óx

Z = (31 - 27)/1.6

= 2.5

Hence, Jacob had the most home runs relative to their usual seasonal average.

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