Question

6) A driver in a car traveling at a speed of 60 mi/h sees a deer 100 m away on the road. Calculate the minimum constant acceleration that is necessary for the car to stop without hitting the deer (assuming that the deer does not move in the meantime).​

Answer 1

Answer:

60miles/h=96560.6m/3600s=27m/s

sf=1/2at^2+v0t+s0

vf=at+v0

t=-v0/a

1/2(v0^2/a)-v0^2/a+s0=0

(v0^2/2a)-v0^2/a=-s0

(V0^2-2V0^2)/2a=-s0

a=-729/-200=4m/s^2