In ANOP, PN = OP and m20 = 32°. Find mZP.
![In ANOP PN OP and m20 32 Find mZP class=](https://us-static.z-dn.net/files/d3d/f593aebad8eb2d108be7461123974ba5.png)
Answer:
m<P = [tex]116^{0}[/tex]
Step-by-step explanation:
The given triangle is an isosceles triangle.
Since PN ≅ OP, then m<O ≅ m<N.
So that,
m<O + m<P + m<N = 180 (sum of angles in a triangle)
But,
m<O = 32 ≅ m<N = 32 (base angles of an isosceles triangle are equal)
32 + 32 + m<P = 180
64 + m<P = 180
m<P = 180 - 64
= 116
m<P = [tex]116^{0}[/tex]