The quantity of heat needed to convert 2.7 moles of ethanol at its boiling point from liquid to vapor is 104.49 kJ
From the question,
We are to calculate the heat needed to convert 2.7 moles of ethanol from liquid to vapor.
Using the formula
Q = n × ΔHvap
Where Q is the quantity of heat
n is the number of moles
and ΔHvap is the enthalpy of vaporization
From the given information,
n = 2.7 moles
and
ΔHvap of ethanol = 38.7 kJ/mol
Putting the parameters into the formula, we get
Q = 2.7 × 38.7
Q = 104.49 kJ
Hence, the quantity of heat needed to convert 2.7 moles of ethanol at its boiling point from liquid to vapor is 104.49 kJ
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