Question

Assume that a procedure yields a binomial distribution with a trial repeated
n
=
5
n
=
5
times. Use some form of technology to find the probability distribution given the probability
p
=
0.578
p
=
0.578
of success on a single trial.

Answer 1

Answer:

P(x = 1) ; binompdf(5, 0.578, 1) = 0.09165

P(x = 2) ;binompdf(5, 0.578, 2) = 0.25107

P(x = 3) ; binompdf(5, 0.578, 3) = 0.34388

P(x = 4) ; binompdf(5, 0.578, 4) = 0.23550

P(x = 5) ; binompdf(5, 0.578, 5) = 0.06451

Explanation:

Using the binomial probability density function on the t84 calculator

binompdf(num_trials, p, x)

Range of x :

x = 0, 1, 2, 3, 4, 5

P(x = 0) ; binompdf(5, 0.578, 0) = 0.01338

P(x = 1) ; binompdf(5, 0.578, 1) = 0.09165

P(x = 2) ;binompdf(5, 0.578, 2) = 0.25107

P(x = 3) ; binompdf(5, 0.578, 3) = 0.34388

P(x = 4) ; binompdf(5, 0.578, 4) = 0.23550

P(x = 5) ; binompdf(5, 0.578, 5) = 0.06451

0.06451+0.23550+0.34388+0.25107+0.09165+0.01338 = 1