Question

What is an equation of a circle whose center is (1,4) and diameter is 10?

Question options:

x2 − 2x + y2 − 8y = 83


x2 − 2x + y2 − 8y = 8


x2 + 2x + y2 + 8y = 8


x2 + 2x + y2 + 8y = 83

Answer 1

Answer:

$x^{2} - 2x + y^{2} - 8y = 8$

Step-by-step explanation:

Standard form for a circle is:

$(x - h)^{2} + (y - k)^{2} = r^{2}$      (h, k) is the center    r is the radius

$(x - 1)^{2} + (y - 4)^{2} = 5^{2} \\x^{2} - 2x + 1 +y^{2} - 8y + 16 = 25\\x^{2} - 2x + y^{2} - 8y = 8$$x^{2} - 2x + y^{2} - 8y = 8$