Question

SHOW WORK
A sample of gas at 62.0°C occupies a volume of 4.80 L at a pressure of 2.90 atm. How many moles of gas are contained in the sample?

Answer 1

PV = nRT —> n = PV/RT

P = 2.90 atm
V = 4.80 L
R = 0.08206 L atm / mol K
T = 62.0 + 273 = 335 K (make sure you convert from celsius to kelvin)

n = (2.90 • 4.80) / (0.08206 • 335) = 0.506 moles of gas