Answer:
6664 g of H₃PO₄
Explanation:
From the question given above, the following data were obtained:
Volume of solution = 4 L
Molarity = 17 M
Mass of H₃PO₄ =?
Next, we shall determine the number of mole of H₃PO₄ in the solution. This can be obtained as follow:
Volume of solution = 4 L
Molarity = 17 M
Mole of H₃PO₄ =?
Molarity = mole /Volume
17 = Mole of H₃PO₄ / 4
Cross multiply
Mole of H₃PO₄ = 17 × 4
Mole of H₃PO₄ = 68 moles
Finally, we shall determine the mass of H₃PO₄ in the solution. This can be obtained as follow:
Mole of H₃PO₄ = 68 moles
Molar mass of H₃PO₄ = (3×1) + 31 + (16×4)
= 3 + 31 + 64
= 98 g/mol
Mass of H₃PO₄ =?
Mole = mass /Molar mass
68 = mass of H₃PO₄ /98
Cross multiply
Mass of H₃PO₄ = 68 × 98
Mass of H₃PO₄ = 6664 g
Thus, the solution contains 6664 g of H₃PO₄
