Question

A hair dryer draws a current of 12.8 A.

(a)How many minutes does it take for
6.8 x 10° C of charge to pass through the
hair dryer? The fundamental charge is
1.602 x 10-19 C.
Answer in units of min.

(b)How many electrons does this amount of
charge represent?
Answer in units of electrons.

Answer 1

Answer:

(a) 8.85×10⁻³ minutes

(b) 4.24×10¹⁹ electrons

Explanation:

(a) Using,

Q = it............................. Equation 1

Where Q = quantity of charge, i = current, t = time.

Make t the subject of the equation

t = Q/i............................. Equation 2

Given: Q = 6.8×10⁰ C, i = 12.8 A

Substitute these values into equation 2

t = 6.8×10⁰/12.8

t = 8.85×10⁻³ minutes

(b) n = Q/(1.602×10⁻¹⁹)................. Equation 3

Where n = number of electrons.

Given: Q = 6.8×10⁰ C

Substitute into equation 2

n = 6.8×10⁰/1.602×10⁻¹⁹

n = 4.24×10¹⁹ electrons

Answer 2

(a) The time taken by the charge to flow from the drier will be $\d8.85$×$\d10^{-3}$minutes

(b) Amount of the electrons in the charge will be  $\d4.24$×$\d10^{19}$ electrons

What will be the time of the charge and number of the electrons in the charge ?

As we know Q = IT

Where Q = quantity of charge, i = current, T = time.

From the above equation

                    T= Q/I.

Given: Q = $6.8\times\d10^{0}$ C, i = 12.8 A

Substitute these values  

T=  $6.8$×$\d10^{0}$ /12.8

T =  $8.85$×$\d10^{-3}$ minutes

Now the number of the electrons present in the charge will be

n = Q/( $1.602$×$\d10^{-19}$)

Where n = number of electrons.

Given: Q = $6.8\times\d10^{0}$ C

Substitute Value of Q  

n =  $6.8\times\d10^{0}$/ $1.602\times\d10^{-19}$

n = $4.24\times\d10^{19}$ electrons

Thus

(a)The time taken by the charge to flow from the drier will be $\d8.85$×$\d10^{-3}$minutes

(b)Amount of the electrons in the charge will be  $\d4.24$×$\d10^{19}$ electrons

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