Respuesta :

tejedordenumeros

Initial considerations

  • Applied force = 50N
  • Distance to equilibrium position = 0.09m
  • Spring constant = ?

Resolution

using hooke's relation

F = K . d

50N = k . 0.09m

k = 50N / 0.09m

k = 5555.56 N/m

Calculating the potential energy of the spring

Ep = 1/2 k . x²

Ep = 1/2 (5555.56 N/m) (0.09m)²

Ep = 22.5 Joules

Answer

the spring constant? =

k =  5555.56 N/m

potential energy of the spring?​

Ep = 22.5 Joules

asuwafohjames

The Potential energy of the spring is 2.25 J

What is the Potential energy of spring?

This is the energy stored in spring due to its elastic properties.

To calculate the potential energy of the spring, we use the formula below.

Formula:

  • E = Fe/2................ Equation 1

Where:

  • E = Potential energy of the spring
  • F = Force applied to the spring
  • e = compression.

From the question,

Given:

  • F = 50 N
  • e = 0.09 m

Substitute these values into equation 1

  • E = 50(0.09)/2
  • E = 2.25 J.

Hence, The Potential energy of the spring is 2.25 J

Learn more about the potential energy of spring: https://brainly.com/question/3510901

Otras preguntas