Question

What is the kinetic energy of a 4 kg cart pushed at a rate of 0.5 m/s?

A. 0.5J

B. 2J

C. 4J

D. 8J​

Answer 1

Answer:

A. 0.5J

Step-by-step explanation:

$K. E._{(cart)} = \frac{1}{2} m {v}^{2} \\ \\K. E._{(cart)} = \frac{1}{2} \times 4 \times (0.5)^{2} \\ \\ K. E._{(cart)} = 2 \times 0.25 \\ \\ K. E._{(cart)} = 0.5 \: J$

Answer 2

The kinetic energy of a 4 kg cart pushed at a rate of 0.5 m/s is 0.5 J.

Kinetic energy = 1 /2 mv²

where

m = mass

v = velocity

Therefore,

m = 4 kg

v = 0.5

Kinetic energy = 1 / 2 × 4 × 0.5²

kinetic energy = 1 / 2 × 4 × 0.25

kinetic energy = 1 / 2 × 1

kinetic energy =  1 /2  = 0.5 j

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