Question

HELP PLEASE!!
Part A: Identify the Minimum, First Quartile, Median, Third Quartile, and Maximum for the data.


64, 53, 60

60, 56, 58

51, 55, 60


A. Minimum: 51, First Quartile: 55, Median: 58, Third Quartile: 60; Maximum: 64

B. Minimum: 51, First Quartile: 55.5, Median: 59, Third Quartile: 60; Maximum: 64

C. Minimum: 51, First Quartile 54.5, Median: 57, Third Quartile: 60; Maximum: 64

D. Minimum: 51, First Quartile: 54, Median: 58, Third Quartile: 60; Maximum: 64

Answer 1

Answer:

Yes! This is my area!

Step-by-step explanation:

Minimum= 51

Maximum=64

To find the median put the numbers in order

51,53,55,58,60,60,64

no cross off one by one to get the middle number

you end up with 58

first quartile is the upper half so that would be 53

third quartile is the lower half so that wou;d be 60

Hope this helps!

Answer 2

Answer:

D

Step-by-step explanation:

when you put them in numerical order, you have 51, 53, 55, 56, 58, 60, 60, 60, 64

the minimum is the smallest number in the data set. the maximum is the largest number in the data set.

the median is the measure of center, which indicates the middle number in the data set

the first quartile is the center of the bottom set of the data

the third quartile is the center of the upper set of the data

(the upper and lower sets are indicated by which side of the median they are on)

hope this helped :)