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I think the answer is A.
I could be wrong but I tried
Hope this helps. :)

The perimeter of qudrilateral ABCD, to the nearest tenth is: 14.6 units.

What is the Perimeter of a Quadrilateral?

Perimeter of a quadrilateral = sum of all its four sides.

Given the qudrilateral with the vertices:

  • A (3, 5)
  • B (1, 3)
  • C (3, -1)
  • D (5, 3)

Use the distance formula, [tex]d = \sqrt{(y_2 - y_1)^2 + (x_2 - x_1)^2}[/tex] to find AB, BC, CD, and AD.

AB = √[(1−3)² + (3−5)²]

AB = √8 = 2.8 units

BC = √[(1−3)² + (3−(−1))²

BC = √20 = 4.5 units

CD = √20 = 4.5 units

AB = √8 = 2.8 units

Perimeter of qudrilateral ABCD = 2.8 + 4.5 + 4.5 + 2.8 = 14.6 units.

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