determing that the compoumd formed is in 100%
therefore, 26.1 +4.3+69.6 = 100%
hence no need of adding O molecule
finding the numbr of moles of each element
no. of moles of C= given mass÷molar mass
=26.1÷12
=2.1 mol
no. of moles of H = given mass÷molar mass
=4.3÷1
=4.3 mol
no of moles of O =given mass÷molar mass
=69.6÷16
=4.3
the simplest whole nber of the element in the unknown compoumd is 1:2:2 of C:H:O
HENCE, the empirical formula is CH2O2
empirical formula mass of CH2O2 IS
=(12)+(2×1)+(16×2)
12+2+32
46 G/MOL
N= molar mass of the compoumd ÷ emporical mass of the compoumd
N= 138÷46
N=3
molecular formula =N×empirical formula
=3 ×CH2O2
C3H6O6 is the molecular formula
(tartonic acid)
hope it helped u!
