Question

Hong hikes at least 1 hour but not more than 4 hours. She hikes at an average rate of 2.7 mph. The function f(t)=2.7tf(t)=2.7t represents the distance she hikes in t hours.



What is the practical range of the function?

all real numbers

all multiples of 2.7 between 2.7 and 10.8, inclusive

all real numbers from 2.7 to 10.8, inclusive

all real numbers from 1 to 4, inclusive

Answer 1

since the range is the value that satisfy the given function. For function f(t) = 2.7t the practical range of the function can be solve by subtituting the lowest time and the highest possible time which is 1 and 4. At t = 1 f(t) = 2.7 and at t = 4 f(t) = 10.8. so the range is all real numbers from 2.7 to 10.8, inclusive

Answer 2

Let

t--------> represents the time in hours

f(t)--------> represents the distance in miles

we know that

$f(t)=2.7t$

The domain of the function is the interval-------->$[1,4]$

$1\ hour \leq t \leq 4\ hours$

Find the range of the function

Find the value of the function for $t=1$

substitute

$f(t)=2.7*1=2.7\ miles$

Find the value of the function for $t=4$

substitute

$f(t)=2.7*4=10.8\ miles$

therefore

The range of the function is the interval-------->$[2.7,10.8]$

$2.7\ miles \leq f(t) \leq 10.8\ miles$

the answer is

The range of the function is all real numbers from 2.7 to 10.8, inclusive