Part 1) we have
[tex]5x+2y=16[/tex] ------> equation A
[tex]x+3y=12[/tex]
[tex]x=12-3y[/tex] ------> equation B
Substitute the equation B in equation A
[tex]5[12-3y]+2y=16[/tex]
[tex]60-15y+2y=16[/tex]
[tex]13y=44[/tex]
[tex]y=44/13=3.38[/tex]
Find the value of x
[tex]x=12-3(44/13)=1.85[/tex]
the best approximation is the point [tex](2.3)[/tex]
therefore
the answer Part 1) is the option C
[tex](2.3)[/tex]
Part 2) we have
[tex]y=-x-2[/tex] ------> equation A
[tex]y=3x+2[/tex] ------> equation B
equate equation A and equation B
[tex]-x-2=3x+2[/tex]
[tex]4x=-4[/tex]
[tex]x=-1[/tex]
Find the value of y
[tex]y=-(-1)-2=-1[/tex]
the solution is the point [tex](-1,-1)[/tex]
therefore
the answer Part 2) is
[tex](-1,-1)[/tex]