Answer: 26.67 m/s
Explanation:
Given
Length traveled by the ball [tex]s=40\ m[/tex]
Time taken to reach the goal post is [tex]t=3\ s[/tex]
Initial velocity [tex]u=0\ m/s[/tex]
Using the second equation of motion
[tex]\Rightarrow s=ut+\frac{1}{2}at^2\\\Rightarrow 40=0+\frac{1}{2}a(3)^2\\\Rightarrow a=\frac{80}{9}\ m/s^2\\[/tex]
Now using
[tex]\Rightarrow v^2-u^2=2as\\\\\Rightarrow v^2-0=2\times \frac{80}{9}\times 40\\\\\Rightarrow v=\sqrt{\dfrac{80\times 80}{9}}=\dfrac{80}{3}\\\Rightarrow v=26.67\ m/s[/tex]
The velocity of ball will be 26.67 m/s
