Respuesta :

Answer:

For a trapezium of height H, parallel side 1 X, and parallel side 2 Y, the area is:

A = (1/2)*H*(X + Y)

with this we can complete the table.

a)

Here we know:

X = 7cm

Y = 11cm

H = 6cm

Then: A = (1/2)*6cm*(7cm + 11cm) = 54 cm^2

b)

Here we know:

X = 8 m

Y = 10 m

A = 126 m^2

Then:

126 m^2 = 0.5*H*(8m + 10m)

126 m^2 = H*9m

126 m^2/9m = H = 14m

Then the height of this trapezoid is 14m

c)

Here we know:

X = 5mm

H = 8mm

A = 72 mm^2

Then:

72 mm^2 = 0.5*8mm*(5mm + Y)

72 mm^2 = 4mm*(5mm + Y)

72mm^2/4mm = 5mm + Y

18 mm = 5mm + Y

18mm - 5mm = Y

13 mm = Y

Then the parallel side 2 is 13 mm long.

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