Question

lol please help i literally cannot do math to save my life

Answer 1

Answer:

$\displaystyle d \approx 3.6$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

Reading a Cartesian Plane

• Coordinates (x, y)

Algebra II

• Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point A(-2, 1)

Point B(1, -1)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

1. Substitute in points [Distance Formula]:                                                        $\displaystyle d = \sqrt{(1+2)^2+(-1-1)^2}$
2. [Distance] [√Radical] (Parenthesis) Add/Subtract:                                        $\displaystyle d = \sqrt{(3)^2+(-2)^2}$
3. [Distance] [√Radical] Evaluate exponents:                                                   $\displaystyle d = \sqrt{9+4}$
4. [Distance] [√Radical] Add:                                                                             $\displaystyle d = \sqrt{13}$
5. [Distance] [√Radical] Evaluate:                                                                      $\displaystyle d = 3.60555127546$
6. [Distance] Round:                                                                                            $\displaystyle d \approx 3.6$

Answer 2

Answer:

3.6 units

Step-by-step explanation:

Point A --> $x_{1}$ = -2 , $y_{1}$ = 1

Point B --> $x_{2}$ = 1   , $y_{2}$ = -1

AB =

$\sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2 } \\\sqrt{[1 - (-2)]^2 + [(-1) - 1]^2} \\\sqrt{3^2 + (-2)^2} \\\sqrt{9 + 4} \\ \sqrt{13} \\3.605$

distance between AB can be rounded to 3.6 units

Hope it helps.