Question

6HCl(aq) + 2A1)
-
3H2(g) + 2AlCl3(aq)
1. How many moles of hydrogen are produced from 1.20 moles of aluminum?

Answer 1

Answer: 1.80 moles of $H_2$ will be produced 1.20 moles of aluminium.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$    

The balanced chemical reaction is:

$6HCl(aq)+2Al(s)\rightarrow 3H_2(g)+2AlCl_3(aq)$  

According to stoichiometry :

2 moles of $Al$ produce = 3 moles of $H_2$

Thus 1.20 moles of $Al$ will produce=$\frac{3}{2}\times 1.20=1.80moles$  of $H_2$

Thus 1.80 moles of $H_2$ will be produced 1.20 moles of aluminium.