Question

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=31°, and CD = 1.6 feet. Find the length of BC to the nearest tenth of a foot.

Answer 1

Answer:

3.1066≈3.1 feet

Step-by-step explanation:

3.1066≈3.1 feet

Answer 2

Answer:

3.1

Step-by-step explanation: