Question

If the radius of Earth were one half what it is now, and the mass were the same, what would be the value of g?

Answer 1

Answer:

4 times what it is now.

Explanation:

g=G(M/r^2)

G is constant, so ignore.

We have (1M/0.5r^2), or 4.

Answer 2

Answer:

4g

Explanation:

the equation of g (field gravity)

g = G M/R²

because G (Contant of Gravitasion) and M (Mass of earth) same, them

g2/g1 = R1²/R2²

g1 = g now

g2 = g which the value we looking for

g2/g = 1/(1/2)²

g2/g = 1/(1/4)

g2/g = 4

g2 = 4g