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In the diagram of triangle ADC below, EB || DC, AE = 9, ED = 5, and AB = 9.2. What is the length of AC, to the nearest tenth?

In the diagram of triangle ADC below EB DC AE 9 ED 5 and AB 92 What is the length of AC to the nearest tenth class=

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Answer:

14.3

Step-by-step explanation:

9/5= 9.2/x (cross multiply)

5 x 9.2= 46

46 ÷ 9 = 5.1

9.2 + 5.1 = 14.3

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