Question

The city was painting a 6 mile section of street. On the first day the painted 2 1/6 miles. On the second day they painted 1 2/3 miles. How much would they have to paint on the third day to complete the painting job?

Answer 1

Answer:

$2\frac{1}{6}$

Step-by-step explanation:

→ Add the distances painted

$2\frac{1}{6} +1\frac{2}{3} =2\frac{1}{6} +1\frac{4}{6} =3\frac{5}{6}$

→ Minus from 6 to find the third day's work

$6-3\frac{5}{6} =\frac{6}{1} -\frac{23}{6} =\frac{36}{6} -\frac{23}{6} =\frac{13}{6} =2\frac{1}{6}$