Question

1.
Calculate the resistance between points A and B (RAB) for the following resistor networks:
Figure 1
All resistors 5000
Figure 2
All resistors 1 k2
Figure 3
A
2k03 352
B В
4700
1000 $
B
A
ww
Figure 6
Figure 4
250 Ω
Figure 5
All resistors 2.2 k12
.B
23003
4700
31000
47002
33003
AW
94002
B

Answer 1

Answer:

The answer is below

Explanation:

1)

$R_{AB}=(500+500)||(500+500)\\\\R_{AB}=1000||1000\\\\R_{AB}=\frac{1000*1000}{1000+1000} \\\\R_{AB}=500\ \Omega$

2)

$R_{AB}=1000\|(1000+1000+1000)\\\\R_{AB}=1000||3000\\\\R_{AB}=\frac{1000*3000}{1000+3000} \\\\R_{AB}=750\ \Omega$

3)

Because of the short, the resistance is zero.

$R_{AB}=0$

4)

$R_{AB}=940\ \Omega$

5)

$R_{AB}=2200||2200||(2200+2200)\\\\R_{AB}=2200||2200||4400\\\\\frac{1}{R_{AB}}=\frac{1}{2200} +\frac{1}{2200} +\frac{1}{4400} \\\\\frac{1}{R_{AB}}=\frac{5}{4400}\\\\R_{AB}=880$

6)

$R_{AB}=(220+100)||470||330\\\\R_{AB}=320||470||330\\\\\frac{1}{R_{AB}}=\frac{1}{320} +\frac{1}{470} +\frac{1}{330} \\\\R_{AB}=120.7\ \Omega$