Answer:
11 seconds
Step-by-step explanation:
h(t) = -16t^2 + 1936
When the brick hits the ground h = 0 so:
-16t^2 + 1936 = 0
-16t^2 = -1936
t^2 = -1936/-16
= 121
t = 11 seconds.
The amount of time taken by the brick to hit the ground is 11 seconds.
A function in mathematics set up a relationship between the dependent variable and independent variable. on changing the value of the independent variable the value of the dependent variable also changes.
It is given that during a building project, a brick is dropped from a height of 1,936 ft. If the equation for height as a function of time is h(t) = -16t² + initial height. where t is time in seconds and h(t) is height in feet.
h(t) = -16t² + 1936
When the brick hits the ground h = 0 then the amount of time taken by the brick will be calculated as below:-
-16t² + 1936 = 0
-16t² = -1936
t² = -1936/-16
t²= 121
t = 11 seconds.
Therefore, the amount of time taken by the brick to hit the ground is 11 seconds.
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