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Find three consecutive odd integers such that four times the middle integer is two less than the sum of the first and third. (Enter your answers as a comma-separated list.)​

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Answer:

The three consecutive odd integers are: -1, 1, 3

Step-by-step explanation:

The three consecutive odd integers be x, x + 2, x + 4

Now according to the question

It is mentioned that

The four times the middle integer is two lower than tfhe sum of the first and third

i.e.

4(x+2) = [x + (x+4)] + 2

4x + 8 = 2x + 6

2x = -2

x = -1

Hence, The three consecutive odd integers are: -1, 1, 3

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