Answer:
1. v₂ = 12.43 m/s
2. I₁ = - 80 N.s
3. I₂ = 80 N.s
Explanation:
Consider the following data given in the question:
m₁ = mass of the Cart 1 = 16 kg
m₂ = mass of the Cart 2 = 7 kg
u₁ = velocity of cart 1 before collision = 4 m/s
u₂ = velocity of cart 2 before collision = 1 m/s
v₁ = velocity of cart 1 after collision = - 1 m/s
v₂ = velocity of cart 2 after collision = ?
1.
Applying the law of conservation of momentum:
[tex]m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}\\(16\ kg)(4\ m/s)+(7\ kg)(1\ m/s)=(16\ kg)(-1\ m/s)+(7\ kg)(v_{2})\\v_{2} = \frac{87\ kg.m/s}{7\ kg}[/tex]
v₂ = 12.43 m/s
2.
Impulse of cart 1 = I₁ = m₁(v₁ - u₁)
I₁ = (16 kg)(- 1 m/s - 4 m/s)
I₁ = - 80 N.s
3.
Impulse of cart 2 = I₂ = m₂(v₂ - u₂)
I₂ = (7 kg)(12.43 m/s - 1 m/s)
I₂ = 80 N.s
