Question

You have a circuit that uses 4 batteries to have a
total voltage of 12V. The circuit is in series, and
has two 25 Ohm resistors and one 10 Ohm
resistor. What is the total resistance of the
circuit? What is the current (amperage) through
the circuit? (Remember: V = IR is the formula
from Ohm's Law)

Answer 1

Answer:

The total resistance of the circuit is 35 ohms and the total current through the circuit is 0.34 A.

Explanation:

Given that,

The total voltage of the 4 batteries = 12 V

Values of resistances are 25 ohm and 10 ohm.

The total resistance in the series combination is given by :

$R_T=R_1+R_2\\\\R_T=25+10\\\\R_T=35\ \Omega$

Let I be the total current through the circuit. It can be solved using Ohm's law as follows :

$V=IR_T\\\\I=\dfrac{V}{R_T}\\\\I=\dfrac{12}{35}\\\\I=0.34\ A$

Hence, this is the required solution.