Question

The area of the hardscape is 3x^2 + 13x + 4. what is the length and width of the hardscape

Answer 1

Answer:

$(3x+1)$

$(x+4)$

Step-by-step explanation:

Assuming that the given surface is two-dimensional, one can simply factor the given polynomial to find the dimensions of the surface.

$3x^2 + 13x + 4$

Just by looking at the polynomial, it is fairly obvious that the factors are;

$(3x+1)(x+4)$

One can check this by distributing, multiply every term in one of the parenthesis by every term in the other. Then combine like terms,

$3x^2 + 12x + x + 4\\\\3x^2 + 13x + 4$

Without further information, it is impossible to determine which is the length, and which is the width, one just knows that the dimensions of the surface are;

$(3x+1)\\\\(x+4)$